loumankc
Caddy
Posts: 38 
TGCT Name: Louis Pittier
Tour: Euro/TST
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Post by loumankc on Jun 3, 2017 22:41:00 GMT -5
you've got 100 yds the wind is 12 mph blowing in your face from 10 o'clock to 4 o'clock. What yardage to you play for 112 or what?
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Post by ErixonStone on Jun 4, 2017 0:35:08 GMT -5
The short answer:
109 if you're aiming left to allow the wind take the ball left-to-right. 114 if you're playing a draw into the wind.
The long answer:
The angle between 6 o'clock (directly in your face) and 4 o'clock is 60-degrees. Cos(60) = 0.5 represents the effect of wind.
With a wedge, wind in your face affects distance by a factor of 1.5 yds/MPH.
So, the amount of distance lost is = Cos(60) * 1.5 yds/MPH * 12 MPH = 9 yds.
100 + 9 = 109 yds
The angle between 3 o'clock and 4 o'clock is 30 degrees. Cos(30) = 0.866 represents the effect of wind.
With a wedge, drawing/fading into a crosswind affects distance by a factor of 0.5 yds/MPH
So, the amount of distance lost is Cos(30) * 0.5 yds/MPH * 12 MPH = 5 yds
100 + 9 + 5 yds = 114 yds
Other factors come into play - elevation, club - that throw this out of the window.
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Post by Generic_Casual on Jun 4, 2017 0:40:15 GMT -5
The short answer: 109 if you're aiming left to allow the wind take the ball left-to-right. 114 if you're playing a draw into the wind. The long answer: The angle between 6 o'clock (directly in your face) and 4 o'clock is 60-degrees. Cos(60) = 0.5 represents the effect of wind. With a wedge, wind in your face affects distance by a factor of 1.5 yds/MPH. So, the amount of distance lost is = Cos(60) * 1.5 yds/MPH * 12 MPH = 9 yds. 100 + 9 = 109 yds The angle between 3 o'clock and 4 o'clock is 30 degrees. Cos(30) = 0.866 represents the effect of wind. With a wedge, drawing/fading into a crosswind affects distance by a factor of 0.5 yds/MPH So, the amount of distance lost is Cos(30) * 0.5 yds/MPH * 12 MPH = 5 yds 100 + 9 + 5 yds = 114 yds Other factors come into play - elevation, club - that throw this out of the window. This is amazing! 😏😏 It made perfect sense because I just smoked. 😂😂 If only I could hit the ball straight! 😊😊 That's still the best reply to a question that I've read in a long time. Well done, sir! 😀😀 |
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Post by xraylucy on Jun 4, 2017 4:51:13 GMT -5
you've got 100 yds the wind is 12 mph blowing in your face from 10 o'clock to 4 o'clock. What yardage to you play for 112 or what? My different calculation which has about the same results: With a perfect headwind with 12mph --> 12 * 1.5 = 18 y added. With a perfect crossheadwind (from 10.30 to 4.30 hrs) with 12mph --> 12 mph / 2 * 1.8 = 10.8 yards added. Since wind blowing from 10.00 o'çlock results in less headwind as from 10.30 hrs in this case i would estimate 9 or 10 yards added. For a perfect crosstailwind i use the factor 1.6. So i've got the correct distances from 8 wind directions and derive other distances from these numbers. |
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Post by bogeyman on Jun 4, 2017 5:59:33 GMT -5
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loumankc
Caddy
Posts: 38
TGCT Name: Louis Pittier
Tour: Euro/TST
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Post by loumankc on Jun 7, 2017 15:22:08 GMT -5
thanks for all the replies, so if the wind was exactly opposite, you would subtract about 8?
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Post by xraylucy on Jun 7, 2017 17:04:05 GMT -5
so 12 mph from 4 to 10 oclock:
12/2*1.6 = 9.6 is the yardage i would subtract if the wind is blowing from 4.30 to 10.30.
Since the tailwind in the actual case is a little less i would take 5*1.6=8 y off.
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Post by xraylucy on Jun 7, 2017 17:05:21 GMT -5
or go to course 'wind test' and do the math yourself. Takes 20 minutes...
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Post by TreeWood on Jun 7, 2017 17:50:01 GMT -5
The short answer: 109 if you're aiming left to allow the wind take the ball left-to-right. 114 if you're playing a draw into the wind. The long answer: The angle between 6 o'clock (directly in your face) and 4 o'clock is 60-degrees. Cos(60) = 0.5 represents the effect of wind. With a wedge, wind in your face affects distance by a factor of 1.5 yds/MPH. So, the amount of distance lost is = Cos(60) * 1.5 yds/MPH * 12 MPH = 9 yds. 100 + 9 = 109 yds The angle between 3 o'clock and 4 o'clock is 30 degrees. Cos(30) = 0.866 represents the effect of wind. With a wedge, drawing/fading into a crosswind affects distance by a factor of 0.5 yds/MPH So, the amount of distance lost is Cos(30) * 0.5 yds/MPH * 12 MPH = 5 yds 100 + 9 + 5 yds = 114 yds Other factors come into play - elevation, club - that throw this out of the window. Well, that explains it then! I've been using Tan instead of Cos!  |
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Post by echomike2 on Jun 8, 2017 3:44:24 GMT -5
The short answer: 109 if you're aiming left to allow the wind take the ball left-to-right. 114 if you're playing a draw into the wind. The long answer: The angle between 6 o'clock (directly in your face) and 4 o'clock is 60-degrees. Cos(60) = 0.5 represents the effect of wind. With a wedge, wind in your face affects distance by a factor of 1.5 yds/MPH. So, the amount of distance lost is = Cos(60) * 1.5 yds/MPH * 12 MPH = 9 yds. 100 + 9 = 109 yds The angle between 3 o'clock and 4 o'clock is 30 degrees. Cos(30) = 0.866 represents the effect of wind. With a wedge, drawing/fading into a crosswind affects distance by a factor of 0.5 yds/MPH So, the amount of distance lost is Cos(30) * 0.5 yds/MPH * 12 MPH = 5 yds 100 + 9 + 5 yds = 114 yds Other factors come into play - elevation, club - that throw this out of the window. Well, that explains it then! I've been using Tan instead of Cos! No wonder my approach shots stink I've been using Ding instead of Dong LOL . I'm glad I saw this I've been trying to use a protractor to calculate winds but in a very simple way. This is a good brake down what about tail wind? |
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